The Length, Width And Diagonal Of A Rectangular Parallelepiped Are 13.4ft., 15.2ft., And 35ft. Respectively. Find The Volume Of The Solid.

The length, width and diagonal of a rectangular parallelepiped are 13.4ft., 15.2ft., and 35ft. respectively. Find the volume of the solid.

Answer:

The answer to this problem is V = 5813.03 ft^3

Step-by-step explanation:

First, a drawing is needed to full understand the problem. See attached photo.

Figure 1 shows the dimensions of the rectangular parallelepiped including the variable h for height and x for the hypotenuse of the length and width. In  order to calculate the volume of this solid, we need to find h. But before we get h, we must first calculate the x.

Refer to figure 2. We can see that it forms a right triangle. Since x is the hypotenuse of the length and width, we will use Pythagorean theorem to solve it.

15.2^2 + 13.4^2 = x^2\\x^2 = 410.6\\x = 20.26 ft

Now refer to figure 3. Since the diagonal, the height and x is forming a right triangle, we can also use Pythagorean theorem to solve h.

x^2 +h^2 = 35^2\\h^2 = 35^2 - 20.26^2\\h^2 = 814.53\\h = 28.54 ft

Finally, we can solve the volume of the solid.

V = lwh\\V = (15.2)(13.4)(28.54)\\V = 5813.03 ft^3

If you want to know more about solid geometry such as finding the surface area and volume of various solid bodies, you may visit the following links:  

brainly.ph/question/2081904  

brainly.ph/question/2076416  

brainly.ph/question/23340  



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